Caledonia County topographic maps

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Saint Johnsbury

United States > Vermont > Caledonia County

St. Johnsbury is located at 44°25′N 72°01′W / 44.417°N 72.017°W / 44.417; -72.017, elevation 212.4 m (697 ft). According to the United States Census Bureau, the town has a total area of 36.8 square miles (95.2 km2), of which 36.4 square miles (94.3 km2) is land and 0.35 square miles (0.9 km2),…

Average elevation: 311 m